iz^2+(2+2i)z+2-1=0

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Solution for iz^2+(2+2i)z+2-1=0 equation:


Simplifying
iz2 + (2 + 2i) * z + 2 + -1 = 0

Reorder the terms for easier multiplication:
iz2 + z(2 + 2i) + 2 + -1 = 0
iz2 + (2 * z + 2i * z) + 2 + -1 = 0

Reorder the terms:
iz2 + (2iz + 2z) + 2 + -1 = 0
iz2 + (2iz + 2z) + 2 + -1 = 0

Reorder the terms:
2 + -1 + 2iz + iz2 + 2z = 0

Combine like terms: 2 + -1 = 1
1 + 2iz + iz2 + 2z = 0

Solving
1 + 2iz + iz2 + 2z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 2iz + iz2 + -1 + 2z = 0 + -1

Reorder the terms:
1 + -1 + 2iz + iz2 + 2z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2iz + iz2 + 2z = 0 + -1
2iz + iz2 + 2z = 0 + -1

Combine like terms: 0 + -1 = -1
2iz + iz2 + 2z = -1

Add '-2z' to each side of the equation.
2iz + iz2 + 2z + -2z = -1 + -2z

Combine like terms: 2z + -2z = 0
2iz + iz2 + 0 = -1 + -2z
2iz + iz2 = -1 + -2z

Reorder the terms:
1 + 2iz + iz2 + 2z = -1 + -2z + 1 + 2z

Reorder the terms:
1 + 2iz + iz2 + 2z = -1 + 1 + -2z + 2z

Combine like terms: -1 + 1 = 0
1 + 2iz + iz2 + 2z = 0 + -2z + 2z
1 + 2iz + iz2 + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
1 + 2iz + iz2 + 2z = 0

The solution to this equation could not be determined.

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